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fix(backfill): an anonymous run says so at the END, where it is read - #53
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Every documented example omitted the API key, and the docs are the smaller half of it: without a key the command SUCCEEDS. It reads the 7 days anonymous access allows, writes 433 rows of Magic Kingdom instead of about 94,000, and exits 0. The existing notice prints before a run that takes minutes, so it scrolls away, and the last thing on screen is `done: 433 rows`. For a customer who has just paid for 400 days that is indistinguishable from success: a file, no error, and a number that means nothing unless you already know what it should have been. A keyless example is worse than a broken one, because a broken one gets reported. The notice is repeated at the end of the run, naming what the key would have bought, and the README and --help export THEMEPARKS_API_KEY before the example that needs it -- while still saying --list does not, since finding a park before you have paid is the point of that flag. Co-Authored-By: Claude Opus 5 (1M context) <noreply@anthropic.com>
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Every documented example omitted the API key. The docs are the smaller half of the problem.
Without a key the command succeeds. It reads the 7 days anonymous access allows, writes 433 rows of Magic Kingdom instead of ~94,000, and exits 0. The notice prints before a run that takes minutes, so it scrolls away, and the last thing on screen is
done: 433 rows.For a customer who has just paid for 400 days that is indistinguishable from success — a file, no error, and a number that means nothing unless you already know what it should have been. A keyless example is worse than a broken one, because a broken one gets reported.
Changed
--helpexport THEMEPARKS_API_KEYbefore the example that needs it, and keep saying--listdoes not — finding a park before you have paid is the point of that flag.213 tests. Companion: ThemeParks_Python#31, and web for the two docs pages.
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